3.32 \(\int \frac{(a+b \sec ^{-1}(c x))^3}{x^5} \, dx\)

Optimal. Leaf size=208 \[ \frac{9 b^2 c^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^2}+\frac{3 b^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^4}+\frac{9 b c^3 \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{32 x}+\frac{3 b c \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{16 x^3}+\frac{3}{32} c^4 \left (a+b \sec ^{-1}(c x)\right )^3-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}-\frac{45 b^3 c^3 \sqrt{1-\frac{1}{c^2 x^2}}}{256 x}-\frac{3 b^3 c \sqrt{1-\frac{1}{c^2 x^2}}}{128 x^3}-\frac{45}{256} b^3 c^4 \sec ^{-1}(c x) \]

[Out]

(-3*b^3*c*Sqrt[1 - 1/(c^2*x^2)])/(128*x^3) - (45*b^3*c^3*Sqrt[1 - 1/(c^2*x^2)])/(256*x) - (45*b^3*c^4*ArcSec[c
*x])/256 + (3*b^2*(a + b*ArcSec[c*x]))/(32*x^4) + (9*b^2*c^2*(a + b*ArcSec[c*x]))/(32*x^2) + (3*b*c*Sqrt[1 - 1
/(c^2*x^2)]*(a + b*ArcSec[c*x])^2)/(16*x^3) + (9*b*c^3*Sqrt[1 - 1/(c^2*x^2)]*(a + b*ArcSec[c*x])^2)/(32*x) + (
3*c^4*(a + b*ArcSec[c*x])^3)/32 - (a + b*ArcSec[c*x])^3/(4*x^4)

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Rubi [A]  time = 0.173491, antiderivative size = 208, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 6, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.429, Rules used = {5222, 4405, 3311, 32, 2635, 8} \[ \frac{9 b^2 c^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^2}+\frac{3 b^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^4}+\frac{9 b c^3 \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{32 x}+\frac{3 b c \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{16 x^3}+\frac{3}{32} c^4 \left (a+b \sec ^{-1}(c x)\right )^3-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}-\frac{45 b^3 c^3 \sqrt{1-\frac{1}{c^2 x^2}}}{256 x}-\frac{3 b^3 c \sqrt{1-\frac{1}{c^2 x^2}}}{128 x^3}-\frac{45}{256} b^3 c^4 \sec ^{-1}(c x) \]

Antiderivative was successfully verified.

[In]

Int[(a + b*ArcSec[c*x])^3/x^5,x]

[Out]

(-3*b^3*c*Sqrt[1 - 1/(c^2*x^2)])/(128*x^3) - (45*b^3*c^3*Sqrt[1 - 1/(c^2*x^2)])/(256*x) - (45*b^3*c^4*ArcSec[c
*x])/256 + (3*b^2*(a + b*ArcSec[c*x]))/(32*x^4) + (9*b^2*c^2*(a + b*ArcSec[c*x]))/(32*x^2) + (3*b*c*Sqrt[1 - 1
/(c^2*x^2)]*(a + b*ArcSec[c*x])^2)/(16*x^3) + (9*b*c^3*Sqrt[1 - 1/(c^2*x^2)]*(a + b*ArcSec[c*x])^2)/(32*x) + (
3*c^4*(a + b*ArcSec[c*x])^3)/32 - (a + b*ArcSec[c*x])^3/(4*x^4)

Rule 5222

Int[((a_.) + ArcSec[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Dist[1/c^(m + 1), Subst[Int[(a + b*x)^n*S
ec[x]^(m + 1)*Tan[x], x], x, ArcSec[c*x]], x] /; FreeQ[{a, b, c}, x] && IntegerQ[n] && IntegerQ[m] && (GtQ[n,
0] || LtQ[m, -1])

Rule 4405

Int[Cos[(a_.) + (b_.)*(x_)]^(n_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)], x_Symbol] :> -Simp[((c +
d*x)^m*Cos[a + b*x]^(n + 1))/(b*(n + 1)), x] + Dist[(d*m)/(b*(n + 1)), Int[(c + d*x)^(m - 1)*Cos[a + b*x]^(n
+ 1), x], x] /; FreeQ[{a, b, c, d, n}, x] && IGtQ[m, 0] && NeQ[n, -1]

Rule 3311

Int[((c_.) + (d_.)*(x_))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(d*m*(c + d*x)^(m - 1)*(
b*Sin[e + f*x])^n)/(f^2*n^2), x] + (Dist[(b^2*(n - 1))/n, Int[(c + d*x)^m*(b*Sin[e + f*x])^(n - 2), x], x] - D
ist[(d^2*m*(m - 1))/(f^2*n^2), Int[(c + d*x)^(m - 2)*(b*Sin[e + f*x])^n, x], x] - Simp[(b*(c + d*x)^m*Cos[e +
f*x]*(b*Sin[e + f*x])^(n - 1))/(f*n), x]) /; FreeQ[{b, c, d, e, f}, x] && GtQ[n, 1] && GtQ[m, 1]

Rule 32

Int[((a_.) + (b_.)*(x_))^(m_), x_Symbol] :> Simp[(a + b*x)^(m + 1)/(b*(m + 1)), x] /; FreeQ[{a, b, m}, x] && N
eQ[m, -1]

Rule 2635

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Sin[c + d*x])^(n - 1))/(d*n),
x] + Dist[(b^2*(n - 1))/n, Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integer
Q[2*n]

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rubi steps

\begin{align*} \int \frac{\left (a+b \sec ^{-1}(c x)\right )^3}{x^5} \, dx &=c^4 \operatorname{Subst}\left (\int (a+b x)^3 \cos ^3(x) \sin (x) \, dx,x,\sec ^{-1}(c x)\right )\\ &=-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}+\frac{1}{4} \left (3 b c^4\right ) \operatorname{Subst}\left (\int (a+b x)^2 \cos ^4(x) \, dx,x,\sec ^{-1}(c x)\right )\\ &=\frac{3 b^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^4}+\frac{3 b c \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{16 x^3}-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}+\frac{1}{16} \left (9 b c^4\right ) \operatorname{Subst}\left (\int (a+b x)^2 \cos ^2(x) \, dx,x,\sec ^{-1}(c x)\right )-\frac{1}{32} \left (3 b^3 c^4\right ) \operatorname{Subst}\left (\int \cos ^4(x) \, dx,x,\sec ^{-1}(c x)\right )\\ &=-\frac{3 b^3 c \sqrt{1-\frac{1}{c^2 x^2}}}{128 x^3}+\frac{3 b^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^4}+\frac{9 b^2 c^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^2}+\frac{3 b c \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{16 x^3}+\frac{9 b c^3 \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{32 x}-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}+\frac{1}{32} \left (9 b c^4\right ) \operatorname{Subst}\left (\int (a+b x)^2 \, dx,x,\sec ^{-1}(c x)\right )-\frac{1}{128} \left (9 b^3 c^4\right ) \operatorname{Subst}\left (\int \cos ^2(x) \, dx,x,\sec ^{-1}(c x)\right )-\frac{1}{32} \left (9 b^3 c^4\right ) \operatorname{Subst}\left (\int \cos ^2(x) \, dx,x,\sec ^{-1}(c x)\right )\\ &=-\frac{3 b^3 c \sqrt{1-\frac{1}{c^2 x^2}}}{128 x^3}-\frac{45 b^3 c^3 \sqrt{1-\frac{1}{c^2 x^2}}}{256 x}+\frac{3 b^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^4}+\frac{9 b^2 c^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^2}+\frac{3 b c \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{16 x^3}+\frac{9 b c^3 \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{32 x}+\frac{3}{32} c^4 \left (a+b \sec ^{-1}(c x)\right )^3-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}-\frac{1}{256} \left (9 b^3 c^4\right ) \operatorname{Subst}\left (\int 1 \, dx,x,\sec ^{-1}(c x)\right )-\frac{1}{64} \left (9 b^3 c^4\right ) \operatorname{Subst}\left (\int 1 \, dx,x,\sec ^{-1}(c x)\right )\\ &=-\frac{3 b^3 c \sqrt{1-\frac{1}{c^2 x^2}}}{128 x^3}-\frac{45 b^3 c^3 \sqrt{1-\frac{1}{c^2 x^2}}}{256 x}-\frac{45}{256} b^3 c^4 \sec ^{-1}(c x)+\frac{3 b^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^4}+\frac{9 b^2 c^2 \left (a+b \sec ^{-1}(c x)\right )}{32 x^2}+\frac{3 b c \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{16 x^3}+\frac{9 b c^3 \sqrt{1-\frac{1}{c^2 x^2}} \left (a+b \sec ^{-1}(c x)\right )^2}{32 x}+\frac{3}{32} c^4 \left (a+b \sec ^{-1}(c x)\right )^3-\frac{\left (a+b \sec ^{-1}(c x)\right )^3}{4 x^4}\\ \end{align*}

Mathematica [A]  time = 0.335836, size = 283, normalized size = 1.36 \[ \frac{9 b c^4 x^4 \left (5 b^2-8 a^2\right ) \sin ^{-1}\left (\frac{1}{c x}\right )+24 b \sec ^{-1}(c x) \left (-8 a^2+2 a b c x \sqrt{1-\frac{1}{c^2 x^2}} \left (3 c^2 x^2+2\right )+b^2 \left (3 c^2 x^2+1\right )\right )+72 a^2 b c^3 x^3 \sqrt{1-\frac{1}{c^2 x^2}}+48 a^2 b c x \sqrt{1-\frac{1}{c^2 x^2}}-64 a^3+72 a b^2 c^2 x^2+24 b^2 \sec ^{-1}(c x)^2 \left (a \left (3 c^4 x^4-8\right )+b c x \sqrt{1-\frac{1}{c^2 x^2}} \left (3 c^2 x^2+2\right )\right )+24 a b^2-45 b^3 c^3 x^3 \sqrt{1-\frac{1}{c^2 x^2}}-6 b^3 c x \sqrt{1-\frac{1}{c^2 x^2}}+8 b^3 \left (3 c^4 x^4-8\right ) \sec ^{-1}(c x)^3}{256 x^4} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*ArcSec[c*x])^3/x^5,x]

[Out]

(-64*a^3 + 24*a*b^2 + 48*a^2*b*c*Sqrt[1 - 1/(c^2*x^2)]*x - 6*b^3*c*Sqrt[1 - 1/(c^2*x^2)]*x + 72*a*b^2*c^2*x^2
+ 72*a^2*b*c^3*Sqrt[1 - 1/(c^2*x^2)]*x^3 - 45*b^3*c^3*Sqrt[1 - 1/(c^2*x^2)]*x^3 + 24*b*(-8*a^2 + b^2*(1 + 3*c^
2*x^2) + 2*a*b*c*Sqrt[1 - 1/(c^2*x^2)]*x*(2 + 3*c^2*x^2))*ArcSec[c*x] + 24*b^2*(b*c*Sqrt[1 - 1/(c^2*x^2)]*x*(2
+ 3*c^2*x^2) + a*(-8 + 3*c^4*x^4))*ArcSec[c*x]^2 + 8*b^3*(-8 + 3*c^4*x^4)*ArcSec[c*x]^3 + 9*b*(-8*a^2 + 5*b^2
)*c^4*x^4*ArcSin[1/(c*x)])/(256*x^4)

________________________________________________________________________________________

Maple [B]  time = 0.342, size = 472, normalized size = 2.3 \begin{align*} -{\frac{{a}^{3}}{4\,{x}^{4}}}-{\frac{{b}^{3} \left ({\rm arcsec} \left (cx\right ) \right ) ^{3}}{4\,{x}^{4}}}+{\frac{3\,{c}^{4}{b}^{3} \left ({\rm arcsec} \left (cx\right ) \right ) ^{3}}{32}}+{\frac{9\,{c}^{3}{b}^{3} \left ({\rm arcsec} \left (cx\right ) \right ) ^{2}}{32\,x}\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}+{\frac{3\,c{b}^{3} \left ({\rm arcsec} \left (cx\right ) \right ) ^{2}}{16\,{x}^{3}}\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}+{\frac{3\,{b}^{3}{\rm arcsec} \left (cx\right )}{32\,{x}^{4}}}-{\frac{45\,{c}^{3}{b}^{3}}{256\,x}\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}-{\frac{3\,c{b}^{3}}{128\,{x}^{3}}\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}-{\frac{45\,{b}^{3}{c}^{4}{\rm arcsec} \left (cx\right )}{256}}+{\frac{9\,{b}^{3}{c}^{2}{\rm arcsec} \left (cx\right )}{32\,{x}^{2}}}-{\frac{3\,a{b}^{2} \left ({\rm arcsec} \left (cx\right ) \right ) ^{2}}{4\,{x}^{4}}}+{\frac{9\,{c}^{4}a{b}^{2} \left ({\rm arcsec} \left (cx\right ) \right ) ^{2}}{32}}+{\frac{9\,a{c}^{3}{b}^{2}{\rm arcsec} \left (cx\right )}{16\,x}\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}+{\frac{3\,a{b}^{2}c{\rm arcsec} \left (cx\right )}{8\,{x}^{3}}\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}+{\frac{3\,a{b}^{2}}{32\,{x}^{4}}}+{\frac{9\,{c}^{2}a{b}^{2}}{32\,{x}^{2}}}-{\frac{3\,{a}^{2}b{\rm arcsec} \left (cx\right )}{4\,{x}^{4}}}-{\frac{9\,{c}^{3}{a}^{2}b}{32\,x}\sqrt{{c}^{2}{x}^{2}-1}\arctan \left ({\frac{1}{\sqrt{{c}^{2}{x}^{2}-1}}} \right ){\frac{1}{\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}}}+{\frac{9\,{c}^{3}{a}^{2}b}{32\,x}{\frac{1}{\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}}}-{\frac{3\,{a}^{2}cb}{32\,{x}^{3}}{\frac{1}{\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}}}-{\frac{3\,{a}^{2}b}{16\,c{x}^{5}}{\frac{1}{\sqrt{{\frac{{c}^{2}{x}^{2}-1}{{c}^{2}{x}^{2}}}}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*arcsec(c*x))^3/x^5,x)

[Out]

-1/4*a^3/x^4-1/4*b^3/x^4*arcsec(c*x)^3+3/32*c^4*b^3*arcsec(c*x)^3+9/32*c^3*b^3*arcsec(c*x)^2/x*((c^2*x^2-1)/c^
2/x^2)^(1/2)+3/16*c*b^3*arcsec(c*x)^2/x^3*((c^2*x^2-1)/c^2/x^2)^(1/2)+3/32*b^3/x^4*arcsec(c*x)-45/256*c^3*b^3*
((c^2*x^2-1)/c^2/x^2)^(1/2)/x-3/128*c*b^3/x^3*((c^2*x^2-1)/c^2/x^2)^(1/2)-45/256*b^3*c^4*arcsec(c*x)+9/32*c^2*
b^3/x^2*arcsec(c*x)-3/4*a*b^2/x^4*arcsec(c*x)^2+9/32*c^4*a*b^2*arcsec(c*x)^2+9/16*c^3*a*b^2*arcsec(c*x)/x*((c^
2*x^2-1)/c^2/x^2)^(1/2)+3/8*c*a*b^2*arcsec(c*x)/x^3*((c^2*x^2-1)/c^2/x^2)^(1/2)+3/32*a*b^2/x^4+9/32*c^2*a*b^2/
x^2-3/4*a^2*b/x^4*arcsec(c*x)-9/32*c^3*a^2*b*(c^2*x^2-1)^(1/2)/((c^2*x^2-1)/c^2/x^2)^(1/2)/x*arctan(1/(c^2*x^2
-1)^(1/2))+9/32*c^3*a^2*b/((c^2*x^2-1)/c^2/x^2)^(1/2)/x-3/32*c*a^2*b/((c^2*x^2-1)/c^2/x^2)^(1/2)/x^3-3/16/c*a^
2*b/((c^2*x^2-1)/c^2/x^2)^(1/2)/x^5

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arcsec(c*x))^3/x^5,x, algorithm="maxima")

[Out]

3/32*a^2*b*((3*c^5*arctan(c*x*sqrt(-1/(c^2*x^2) + 1)) + (3*c^8*x^3*(-1/(c^2*x^2) + 1)^(3/2) + 5*c^6*x*sqrt(-1/
(c^2*x^2) + 1))/(c^4*x^4*(1/(c^2*x^2) - 1)^2 - 2*c^2*x^2*(1/(c^2*x^2) - 1) + 1))/c - 8*arcsec(c*x)/x^4) - 1/4*
a^3/x^4 - 1/16*(4*b^3*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^3 - 3*b^3*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^
2*x^2)^2 + 12*(2*(c^2*log(c*x + 1) + c^2*log(c*x - 1) - 2*c^2*log(x) + 1/x^2)*a*b^2*c^2*log(c)^2 + 64*b^3*c^2*
integrate(1/16*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))/(c^2*x^7 - x^5), x)*log(c)^2 - 64*b^3*c^2*integrate(1/1
6*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^2*x^2)/(c^2*x^7 - x^5), x)*log(c) + 128*b^3*c^2*integrate(1/16
*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(x)/(c^2*x^7 - x^5), x)*log(c) - 64*a*b^2*c^2*integrate(1/16*x^2*l
og(c^2*x^2)/(c^2*x^7 - x^5), x)*log(c) + 128*a*b^2*c^2*integrate(1/16*x^2*log(x)/(c^2*x^7 - x^5), x)*log(c) -
64*b^3*c^2*integrate(1/16*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^2*x^2)*log(x)/(c^2*x^7 - x^5), x) + 64
*b^3*c^2*integrate(1/16*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(x)^2/(c^2*x^7 - x^5), x) - 64*a*b^2*c^2*in
tegrate(1/16*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^2/(c^2*x^7 - x^5), x) + 16*b^3*c^2*integrate(1/16*x^2*arc
tan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^2*x^2)/(c^2*x^7 - x^5), x) + 16*a*b^2*c^2*integrate(1/16*x^2*log(c^2*x^
2)^2/(c^2*x^7 - x^5), x) - 64*a*b^2*c^2*integrate(1/16*x^2*log(c^2*x^2)*log(x)/(c^2*x^7 - x^5), x) + 64*a*b^2*
c^2*integrate(1/16*x^2*log(x)^2/(c^2*x^7 - x^5), x) - (2*c^4*log(c*x + 1) + 2*c^4*log(c*x - 1) - 4*c^4*log(x)
+ (2*c^2*x^2 + 1)/x^4)*a*b^2*log(c)^2 - 64*b^3*integrate(1/16*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))/(c^2*x^7 - x
^5), x)*log(c)^2 + 64*b^3*integrate(1/16*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^2*x^2)/(c^2*x^7 - x^5), x)*
log(c) - 128*b^3*integrate(1/16*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(x)/(c^2*x^7 - x^5), x)*log(c) + 64*a*b
^2*integrate(1/16*log(c^2*x^2)/(c^2*x^7 - x^5), x)*log(c) - 128*a*b^2*integrate(1/16*log(x)/(c^2*x^7 - x^5), x
)*log(c) - 16*b^3*integrate(1/16*sqrt(c*x + 1)*sqrt(c*x - 1)*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^2/(c^2*x^7 -
x^5), x) + 4*b^3*integrate(1/16*sqrt(c*x + 1)*sqrt(c*x - 1)*log(c^2*x^2)^2/(c^2*x^7 - x^5), x) + 64*b^3*integr
ate(1/16*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^2*x^2)*log(x)/(c^2*x^7 - x^5), x) - 64*b^3*integrate(1/16*a
rctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(x)^2/(c^2*x^7 - x^5), x) + 64*a*b^2*integrate(1/16*arctan(sqrt(c*x + 1)
*sqrt(c*x - 1))^2/(c^2*x^7 - x^5), x) - 16*b^3*integrate(1/16*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))*log(c^2*x^2)
/(c^2*x^7 - x^5), x) - 16*a*b^2*integrate(1/16*log(c^2*x^2)^2/(c^2*x^7 - x^5), x) + 64*a*b^2*integrate(1/16*lo
g(c^2*x^2)*log(x)/(c^2*x^7 - x^5), x) - 64*a*b^2*integrate(1/16*log(x)^2/(c^2*x^7 - x^5), x))*x^4)/x^4

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Fricas [A]  time = 2.34434, size = 512, normalized size = 2.46 \begin{align*} \frac{72 \, a b^{2} c^{2} x^{2} + 8 \,{\left (3 \, b^{3} c^{4} x^{4} - 8 \, b^{3}\right )} \operatorname{arcsec}\left (c x\right )^{3} - 64 \, a^{3} + 24 \, a b^{2} + 24 \,{\left (3 \, a b^{2} c^{4} x^{4} - 8 \, a b^{2}\right )} \operatorname{arcsec}\left (c x\right )^{2} + 3 \,{\left (3 \,{\left (8 \, a^{2} b - 5 \, b^{3}\right )} c^{4} x^{4} + 24 \, b^{3} c^{2} x^{2} - 64 \, a^{2} b + 8 \, b^{3}\right )} \operatorname{arcsec}\left (c x\right ) + 3 \,{\left (3 \,{\left (8 \, a^{2} b - 5 \, b^{3}\right )} c^{2} x^{2} + 16 \, a^{2} b - 2 \, b^{3} + 8 \,{\left (3 \, b^{3} c^{2} x^{2} + 2 \, b^{3}\right )} \operatorname{arcsec}\left (c x\right )^{2} + 16 \,{\left (3 \, a b^{2} c^{2} x^{2} + 2 \, a b^{2}\right )} \operatorname{arcsec}\left (c x\right )\right )} \sqrt{c^{2} x^{2} - 1}}{256 \, x^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arcsec(c*x))^3/x^5,x, algorithm="fricas")

[Out]

1/256*(72*a*b^2*c^2*x^2 + 8*(3*b^3*c^4*x^4 - 8*b^3)*arcsec(c*x)^3 - 64*a^3 + 24*a*b^2 + 24*(3*a*b^2*c^4*x^4 -
8*a*b^2)*arcsec(c*x)^2 + 3*(3*(8*a^2*b - 5*b^3)*c^4*x^4 + 24*b^3*c^2*x^2 - 64*a^2*b + 8*b^3)*arcsec(c*x) + 3*(
3*(8*a^2*b - 5*b^3)*c^2*x^2 + 16*a^2*b - 2*b^3 + 8*(3*b^3*c^2*x^2 + 2*b^3)*arcsec(c*x)^2 + 16*(3*a*b^2*c^2*x^2
+ 2*a*b^2)*arcsec(c*x))*sqrt(c^2*x^2 - 1))/x^4

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{asec}{\left (c x \right )}\right )^{3}}{x^{5}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*asec(c*x))**3/x**5,x)

[Out]

Integral((a + b*asec(c*x))**3/x**5, x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arcsec}\left (c x\right ) + a\right )}^{3}}{x^{5}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arcsec(c*x))^3/x^5,x, algorithm="giac")

[Out]

integrate((b*arcsec(c*x) + a)^3/x^5, x)